Making a list of evenly spaced numbers in a certain range in python
158,780
Solution 1
Given numpy, you could use linspace:
Including the right endpoint (5):
In [46]: import numpy as np
In [47]: np.linspace(0,5,10)
Out[47]:
array([ 0. , 0.55555556, 1.11111111, 1.66666667, 2.22222222,
2.77777778, 3.33333333, 3.88888889, 4.44444444, 5. ])
Excluding the right endpoint:
In [48]: np.linspace(0,5,10,endpoint=False)
Out[48]: array([ 0. , 0.5, 1. , 1.5, 2. , 2.5, 3. , 3.5, 4. , 4.5])
Solution 2
You can use the following approach:
[lower + x*(upper-lower)/length for x in range(length)]
lower and/or upper must be assigned as floats for this approach to work.
Solution 3
Similar to unutbu's answer, you can use numpy's arange function, which is analog to Python's intrinsic function range
. Notice that the end point is not included, as in range
:
>>> import numpy as np
>>> a = np.arange(0,5, 0.5)
>>> a
array([ 0. , 0.5, 1. , 1.5, 2. , 2.5, 3. , 3.5, 4. , 4.5])
>>> a = np.arange(0,5, 0.5) # returns a numpy array
>>> a
array([ 0. , 0.5, 1. , 1.5, 2. , 2.5, 3. , 3.5, 4. , 4.5])
>>> a.tolist() # if you prefer it as a list
[0.0, 0.5, 1.0, 1.5, 2.0, 2.5, 3.0, 3.5, 4.0, 4.5]
Solution 4
f = 0.5
a = 0
b = 9
d = [x * f for x in range(a, b)]
would be a way to do it.
Solution 5
You can use the folowing code:
def float_range(initVal, itemCount, step):
for x in xrange(itemCount):
yield initVal
initVal += step
[x for x in float_range(1, 3, 0.1)]
Author by
Double AA
Updated on July 29, 2022Comments
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Double AA almost 2 years
What is a pythonic way of making list of arbitrary length containing evenly spaced numbers (not just whole integers) between given bounds? For instance:
my_func(0,5,10) # ( lower_bound , upper_bound , length ) # [ 0, 0.5, 1, 1.5, 2, 2.5, 3, 3.5, 4, 4.5 ]
Note the
Range()
function only deals with integers. And this:def my_func(low,up,leng): list = [] step = (up - low) / float(leng) for i in range(leng): list.append(low) low = low + step return list
seems too complicated. Any ideas?
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unutbu almost 13 years@Double AA: True; if you need a list, you could use
np.linspace(0,5,10).tolist()
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nvd over 9 yearsOr simply: a = N.arange(0, 5 , 0.5).tolist()
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feedMe about 8 yearsNice to have a concise stock python alternative in case numpy is not available.
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lhcgeneva over 7 yearsCareful when using numpy.arange(), though, endpoints are not handled consistently, giving rise to unreliable behavior, see here.
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Trav almost 6 yearsthis updated version produces the exact same output as numpy linspace:
[lower + x*(upper-lower)/(length-1) for x in range(length)
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Bandham Manikanta over 4 yearsfor integers, np.arange(0, 5, 1). and for floating numbers, np.arange(0, 5, 1.0)